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Showing content with the highest reputation on 10/15/18 in all areas

  1. Pentru cei care nu stiu, a inceput ECSC 2018, la Londra. E vorba de un concurs european, CTF, cu multe tari europene participante. In ultimii doi ani, Romania a luat locul II, sper ca anul acesta sa ia primul loc. Si sper ca la anul, cand Romania va organiza acest concurs, sa va inscrieti mai multi. Pagina echipei Romaniei, pentru a fi la curent cu ce se intampla: https://www.facebook.com/ECSC2018/
    3 points
  2. Nu-s erori de niciun fel. @Nytro,verifică treaba cu cachingul. Sunt aproape sigur că de la aia e.
    1 point
  3. Solutie temporara: dai un refresh dupa ce ai intrat pe feed si isi revine
    1 point
  4. Asa patesc si eu de fiecare data cand intru pentru cateva secunde de cand s-a bagat acest feed.
    1 point
  5. Am inteles. O sa incerc sa implementez asta. Multumesc 🙂
    1 point
  6. Ai gresit query-ul baiatul meu. Incearca sa-i dai select username, password from administrator.users where username='userultau' and password='parolata'; Sau, e de preferat sa folosesti Prepared Statement, pt ca e mai frumix, mai ales cand ai nevoie de parametri Ar trebui sa scrii ceva de genul PreparedStatement stmt="SELECT username, password FROM ADMINISTRATOR.users where username=? and password=?;"; stmt.setString(1,VARIABILA_USERNAME); stmt.setString(2,VARIABILA_PAROLA); rs=stmt.execute... si de aici te descurci Btw, avand in vedere ca ai un db, ar trb sa ai coloana de username UNICA, Deci daca tu dai select, ar trebui sa primesti MAXIM UN REZULTAT, deci tu poti doar sa verifici doar if(rs.next()){ inseamna ca ti-a returnat un rezultat, si avant in vedere ca i-ai specificat din prima username-ul si parola, ar trebui sa fie ok; deci iti bagi aici codul tau drumi; } BTW, ai grija la contains. Incearca sa folosesti String.equals(AltString); Pt ca daca eu am ca si user si ca si parola, un substring din alt user si alta parola, m-as putea log. BTW 2; }catch (SQLException err) { System.out.println(err.getMessage() ); } da-i cu err.printStackTrace(); in loc de sysout err.getmessage
    1 point
  7. Download: imap brute checker password: blackos.net Work only without a proxy or SOCKS4 / SOCKS5 Yes, even though the title contains the phrase ALLMAILCHECKER , but I will not lie to it wrong, it all depends on the number of IMAP settings in the imapdatabase.cfg file (there are about 57k settings there now). The software works exclusively using the IMAP protocol, which means that when purchasing a proxy, pay attention to the prescription to the proxy or if there is no mention of this, check with the support if their proxy can work with the imap protocol, whether this feature is blocked. The software searches for letters using 2 methods: 1 fast (less efficient) using search by sender with one request (as in all mail you just type in @ ea.com press Enter and it gives the result). 2 Long (more efficient) using the passage through all the letters in search of the sender you need. (use forced search to activate this search method) Why 2 methods? It’s just that not all IMAP servers support the first method, so you probably noticed in similar software (not all starjieu have a special thank you for you. I didn’t skip such mails, I implemented the second method, but it takes much longer to check than the first one, because I have to go through all the letters, there’s a limit to how many emails you can get for this.
    -1 points
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