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Se da urmatoarea arhiva -----BEGIN PGP SIGNED MESSAGE----- Hash: SHA256 begin 755 bomb.gz M'XL("%,5[T\"`V)O;6(`Q5,Q:Q1!%'Y[=X;+P6%$HZ#-7*/AD,1`.HEBT*N4 M@%T:E]W;T2S<W8;=64PJU\(BX$%2I+W_D"[&1A#L#EL[+05M`A9VZ_MF9F4X M4MCYX,V;[WWOO9V[^>;5H\<]S_.HLAK5">AUT6BN<6S63'Z-!'-+-&=Y;5P# M_\5;^`7D%DCS.G?`'/M/WL/G+'_2X/@>5=/BXP';N#TY;#1/+W/F^]>R+,?M M8^`5X,^,3^IH0/<[S#L]TJVK'];GF<BO3(MQ>Q\-5]$PX88?"^.V0F81F;<8 MX54CI@7]9^MVNQN;FT\Z8BO)12^(!S+JM#:282@>QEF0#F4D?'^%W20?V`Q, MM$R)4-M2A#/='/E8I'+W2NGZ2I["OQ,DYEUKHG:#G;&ZH@Y*A2$[>KG9*[ MBI:C0`7_?O8;9.X7=ZGX[A5DX/`-&SNVKE[IP&I@MNZ2K:GL&S?=<K#GQ)J3 M_\W@CF<T=]'.8VG1_,R\)2:>G3/O/,/O(=UOJG!N@VM&TQ;C)/@N%%;A%J]' M?R>=E3C3OL-#VQ,'7^/UV,'7G>_C:X+CFZ+B/;H)^3KX-J]?'(RW^LG!=R%\ M!]^W;]H\08]Z^*\/*WQ6/IW!6S.8POPY/,,RH"C.B&5(44([:3Q2I&5+6G4D D=W<&2211A)HD5^1G*D@Y^&&657NIE>?+441_``N*M.R&!``` ` end -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.10 (GNU/Linux) iF4EAREIAAYFAk/vFbgACgkQiOFy19RY1SC0xQD7BXcnDyh3is1d8ghAMZIgxgsN hjGpSPagtvwfGznRdsMA/04FmPk8U7FimmEFtddOt8xVRjiJskwknvye/i+AJe5d =YStz -----END PGP SIGNATURE----- Se cere practic sa faceti in asa fel incat atunci cand executabilul vine rulat bomba sa nu explodeze Un exemplu [pyth0n3@mc]$ ./bomb Bomb Armed ______ Disarm the bomb by cutting the correct wires > test ***BOOM! You Failed! [pyth0n3@mc]$ Cei care rezolva problema sunt rugati posteze dar sa nu publice metoda momentan oferind o sansa si celorlati.Cand acest challenge se va termina voi publica sursa si metodele.Codul poate fi executat doar in Linux , in procesoarele Intel 32 biti si a fost scris in assembly.Daca aveti intrebari sunteti liberi sa le faceti, (apropo data trecuta o singura persoana ma intrebat cum sa extraga executabilul din arhiva , l-am codat in ascii nu este criptat , acest lucru permite ca un executabil sa fie introdus intrun host care suporta doar text sau chiar intrun forum ) Bafta! Later Edit : Am tradus codul si pentru procesoarele 64 bit Intel pentru cei care prefera sa il ruleze in sisteme 64 bit. -----BEGIN PGP SIGNED MESSAGE----- Hash: SHA256 begin 755 bomb64.gz M'XL("-`I[T\"`V)O;6(V-`#%E#%/VT`4QY^=)B)9TBJJ0.UR66@55:DJ=8@$ MA8#:R!*ID+JQU-CQM5A*8F2?59C8.[$P\048\Q$"E6(&O@$+;$AE86%U[\XO MJ7TD[="A3[I[?K][_W>.]5X./K1;NJ;!V'18`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`/J[@>+#KNWT&<KQ!3B?0O=VNYU"1)'*\D($9,,OGSK2#8/Q, /Y82:M._`+P<9IAH&!@`` ` end -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.10 (GNU/Linux) iF4EAREIAAYFAk/vKh4ACgkQiOFy19RY1SBiLgD+NA4JQvMF1BtMjl9YPffVuDdq WKvze0HIdlG4dnBeec8A/iODzvPUrdHElMvVuzfBnG5B3/tbzAt52aKakmP3NoVV =0F1P -----END PGP SIGNATURE----- Tin sa precizez, pentru a rezolva problema programul ar trebui sa stampeze urmatorul cod Bomb Disarmed __/ __ Vreau doar sa mai adaug faptul ca nu exista doar o singura metoda ci mai multe , asta depinde doar de imaginatia pe care o aveti.Oricum rezolvand aceasta problema va veti da seama ca multe chestii merg pe acest principiu.