Jump to content
cmiN

[Python] Script de inversat octeti (cmiN) RO-comm

Recommended Posts

Posted

#! /usr/bin/env python
# 20.07.2009 <> 20.07.2009 | cmiN
# Challenge 4 Hertz @ rstcenter.com

__doc__="""
This library encodes / decodes a file by reversing the bytes read from it.\n
"""
__usage__="""
Usage:
byte.py filename.ext method lineswitch type

Method:

b - reverse bytes: A3 C4 5D -> 3A 4C D5

l - reverse lines: A3 C4 5D -> 5D C4 A3

r - reverse rows : A3 C4 5D 6B 2C 3F
2E D3 1A -> 2E D3 1A
6B 2C 3F A3 C4 5D

Lineswitch:

ON - Reverse also the LineFeed byte (new line)
OFF - Don't change the LineFeed position

Type:

A - ASCII
B - BINARY
"""

import os, sys

def reverse(filepath, mode, switch, flag):
if flag=="A":
flag=""
else:
flag="b"
infile=open(filepath, "r"+flag) #0x03 Deschidem fisierul din locatia citita si
inbytes=infile.readlines() # ii citim octetii linie cu linie.
infile.close()
for x in range(len(inbytes)): #0x04 Spargem fiecare linie in lista, apoi
l=[] # convertim octetii, obtinand in final
l[:]=inbytes[x] # o lista ce contine liste ce contin
inbytes[x]=l # string-uri cu reprezentarea hexadecimala a fiecarui octet.
for y in range(len(inbytes[x])):
z=hex(ord(inbytes[x][y]))[2:]
while len(z)<2:
z="0"+z
inbytes[x][y]=z
if switch=="OFF":
for x in inbytes:
try:
x.remove("0a")
except:
status=True
else:
status=False
if "r" in mode: #0x05 In functie de modul ales inversam
inbytes.reverse() # pozitia si rasturnam octeti.
if "l" in mode:
for x in inbytes:
x.reverse()
if "b" in mode:
for x in inbytes:
for y in range(len(x)):
x[y]=x[y][::-1]
if switch=="OFF":
for x in inbytes:
x.append("0a")
if status:
inbytes[len(inbytes)-1].remove("0a")
outbytes=""
for x in inbytes: #0x06 Convertim fiecare string inapoi in octet,
for y in x: # apoi ii scriem pe toti intr-un fisier
outbytes+=chr(int(y, 16)) # cu nume si extensie inversata.
outfile=open(infile.name[::-1], "w"+flag)
outfile.write(outbytes)
outfile.close()
print("Ready! Check %s" % outfile.name)
del filepath, mode, switch, flag, infile, inbytes, x, y, z, outbytes, outfile

def main():
if len(sys.argv)!=5: #0x02 Citim argumentele furnizate de user si
print(__doc__) # daca avem suficiente apelam functia reverse()
print(__usage__) # cu argumentele ce contin locatia unui fisier si modul preferat.
else:
reverse(sys.argv[1], sys.argv[2], sys.argv[3], sys.argv[4])

if __name__=="__main__":
try: #0x01 Executam functia main(), exceptand orice erroare
main() # poate aparea pe parcurs.
except WindowsError:
print("An error occurred!")
os.system("pause >NUL") #0x00 Pauza de final pentru citirea output-ului.

*** sursa editata ***

Updated to: 22.07.2009

Posted

Vezi ca am dat edit la sursa, si am facut-o ceva mai complexa. Ideea este ca am pus acea sursa cu scop educativ, in invatarea unor chestii din programarea in python, pentru incepatori ajuta sa inteleaga mai bine cum sa se joace cu listele si cu array-uri etc. Si ce ai vazut tu reprezinta numai o bucatica din ce am in minte sa fac. Putini stiu sau intereseaza python pe forumul asta, deci incep sa ma bag si eu in seama cu cate ceva pe langa tot c++ si borland delphi, vb, chestii black hat sau ce mai vedeti si voi :P. Mai ales ca e si comentata in romana, deci sigur ajuta pe cineva.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.



×
×
  • Create New...