youjnhuhn2
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Posts posted by youjnhuhn2
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Dupa cum spune si titlul: Steam Community :: SkyDeldro
https://steamdb.info/calculator/76561198047057965/
Singura problema este ca are VAC ban pe CS:GO in rest totul e in regula, are si marchet activat.
Pretul oferiti-l voi..astept pm
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Buna am si eu o problema daca ma poate ajuta cineva cu ceva calcul/relatii de calcul.
Calculand sarcina pe care o pot dezvolta diverse baterii (1.5V si 12V), calculati numarul de condensatoare de 1000uF conectate in paralel, necesare stocarii aceleasi sarcini, alimentate la tensiunea inscrisa pe baterie.
Nu prea stiu ce si cum sa incep
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si unde ma loghez?
xbox360
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Am venit cu inca 4:
Qf/uQf11SDgseDgsSGXofH1oAskgDtQIOgHggh1oiDkGif0TOg3siGXGTsgqbfP6S456S4/JifXifH59DGzuiYkhAk0hg8K9iHAGDskgAf6Me8W6SGGtQfPuQfPqb4nuDJ0DOgPNeGW9iHXLef0IOgblb459gGAPAgLTQf11T2gseDgsShzNAkzmfDkMAJkOOgQGTtPuTskhHhXDOH/NfHLDSWCC
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Dupa cum spune titlul
1) 2KF2H2-Z9HF-BRJ9G2-2MGJ-MJF7HZ
2) TKD8FK-D9ZJ-R7ZTGW-PDWM-DTPV4C
3) PCYWPB-KP6C-7DWZ2H-2N6P-JTV8CF
4) D4EVT8-ZPPR-6ZKW9F-44EC-TT6GY2
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matematic e cam imposibil sa imparti 25 de cai vii si intregi in 4 grajduri
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din pacate doar atatea am primit
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https://www.facebook.com/SpaceComGame/app_174961479209942
like si primiti key
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Daca imi dai un motiv destul de bun incat sa nu le dau pe steam market cu 1.60euro iti dau 50 de keys )))
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https://www.facebook.com/Bianca9211
daca intereseaza pe cineva
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si totusi care e poanta?
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imi poate spune cineva un vpn cu care pot face cont sa pot juca jocuri pentru ca-mi zice ca nu sunt available in my region
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poate folosesc proxy uita-te in Internet options -> Connections -> Lan settings si daca e bifat Proxy
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Oust tu in ce clasa esti de vi cu matrici d-astea ? clasa 9 ?
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ceva dovezi de plata ? Ce se mai stie despre site?
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Pasul 1: http://postimg.org/image/69avujm7h/
Pasul 2: Logare/ DreamSpark/ StartDownload
http://postimg.org/image/o05n4p1zt/
Pasul 3: Profita! De aici va descurcati
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http://postimg.org/image/vqhfjqqin/
uite mailul de confirmare
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Index of / inregistrat azi
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10euro trebuie sa platesti daca nu detii domeniu si vrei sa inregistrezi unul nou. De ce nu te uiti mai intai si dupa aceea sa comentezi ?
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Take the integral:
integral csc(x+1) csc(x+2) dx
Write csc(x+1) csc(x+2) as 2/(cos(1)-cos(2 x+3)):
= integral 2/(cos(1)-cos(2 x+3)) dx
Factor out constants:
= 2 integral 1/(cos(1)-cos(2 x+3)) dx
For the integrand 1/(cos(1)-cos(2 x+3)), substitute u = 2 x+3 and du = 2 dx:
= integral 1/(cos(1)-cos(u)) du
For the integrand 1/(cos(1)-cos(u)), substitute s = tan(u/2) and ds = 1/2 sec^2(u/2) du. Then transform the integrand using the substitutions sin(u) = (2 s)/(s^2+1), cos(u) = (1-s^2)/(s^2+1) and du = (2 ds)/(s^2+1):
= integral 2/((s^2+1) (cos(1)-(1-s^2)/(s^2+1))) ds
Simplify the integrand 2/((s^2+1) (cos(1)-(1-s^2)/(s^2+1))) to get 2/(s^2+s^2 cos(1)-1+cos(1)):
= integral 2/(s^2+s^2 cos(1)-1+cos(1)) ds
Factor out constants:
= 2 integral 1/(s^2+s^2 cos(1)-1+cos(1)) ds
Factor cos(1)-1 from the denominator:
= 2 integral 1/((cos(1)-1) ((s^2 (1+cos(1)))/(cos(1)-1)+1)) ds
Factor out constants:
= 2/(cos(1)-1) integral 1/((s^2 (1+cos(1)))/(cos(1)-1)+1) ds
For the integrand 1/((s^2 (1+cos(1)))/(cos(1)-1)+1), substitute p = s cot(1/2) and dp = cot(1/2) ds:
= (2 tan(1/2))/(cos(1)-1) integral 1/(1-p^2) dp
The integral of 1/(1-p^2) is tanh^(-1)(p):
= (2 tan(1/2) tanh^(-1)(p))/(cos(1)-1)+constant
Substitute back for p = s cot(1/2):
= csc(1/2) sec(1/2) (-tanh^(-1)(s cot(1/2)))+constant
Substitute back for s = tan(u/2):
= csc(1/2) sec(1/2) (-tanh^(-1)(cot(1/2) tan(u/2)))+constant
Substitute back for u = 2 x+3:
= csc(1/2) sec(1/2) (-tanh^(-1)(cot(1/2) tan(x+3/2)))+constant
Which is equivalent for restricted x values to:
Answer: |
| = csc(1) (log(sin(x+1))-log(sin(x+2)))+constant
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csc(1) log(sin(1+x))-csc(1) log(sin(2+x))+C
Descarcare cursuri Udemy gratis
in Tutoriale in romana
Posted
are cineva sau ma poate ajuta cu: https://www.udemy.com/learn-linux-in-5-days/