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Mai erau de adaugat o groaza de algoritmi dar ajunge atat. Multumesc pentru ajutor @nedo #include<iostream> #include<conio.h> #include<math.h> #include<vector> #include<string> using namespace std; int main(){ int alege,prog=0,n,test=0,test1,test2=1,w,z,r; float a,b,c,x1,x2,delta,x,real,img; char alege1,ec; string input; char choise = ' '; restart: cout <<"1.Calculator\n"; cout <<"2.Ecuatia de gradul intai\n"; cout <<"3.Ecuatia de gradul 2\n"; cout <<"4.Progresii\n"; cout <<"5.Cmmdc\n"; cout <<"6.Exit\n"; cout <<"Alege (1,2,3..6): ";cin>>alege; switch(alege){ case 1 : cout <<"\nFelicitari , ai ales 'Calculatorul'\n\n"; operatii: cout <<"a)Inmultire\n"; cout <<"b)Impartire\n"; cout <<"c)Adunare\n"; cout <<"d)Scadere\n"; cout <<"Alege operatia dorita: ";cin>>alege1; switch(alege1){ case 'a' : cout <<"Ai ales operatia de inmultire calculeaza acum\n"; cout <<"a=";cin>>a; cout <<"b=";cin>>b; cout <<"Rezultatul este " <<a*b<<endl; break; case 'b' : cout <<"Ai ales operatia de impartire calculeaza acum\n"; cout <<"a=";cin>>a; cout <<"b=";cin>>b; cout <<"Rezultatul este " <<a/b<<endl; break; case 'c' : cout <<"Ai ales operatia de adunare calculeaza acum\n"; cout <<"a=";cin>>a; cout <<"b=";cin>>b; cout <<"Rezultatul este " <<a+b<<endl; break; case 'd' : cout <<"Ai ales operatia de scadere calculeaza acum\n"; cout <<"a=";cin>>a; cout <<"b=";cin>>b; cout <<"Rezultatul este " <<a-b<<endl; break; default : cout <<"Alegere gresita . Alege doar dintre 'a' , 'b' , 'c' si 'd'";} break; cout <<"\nDoresti sa revii in meniul de operatii ?[Y/N]"; choise=_getch(); if (choise == 'n') goto operatii; case 2 : cout <<"Felicitari , ai ales 'Ecuatia de gradul intai'\n"; cout <<"Alege tipul de ecuatie\n"; cout <<"a) ax+b=0\n"; cout <<"Alege : "; cin>>ec; if (ec == 'a'){ cout<<"Dati valoarea lui a = "; cin>>a; cout<<"Dati valoarea lui b = "; cin>>b; if (a == 0) if (b == 0) cout <<"Ecuatie nedeterminata"; else cout <<"Ecuatie imposibila"; else { x=-b/a; cout <<"Rezultatul este: "<<x<<endl;}} break; case 3 : cout <<"Felicitari , ai ales 'Ecuatia de gradul doi'\n"; cout <<"a=";cin>>a; cout <<"b=";cin>>b; cout <<"c=";cin>>c; delta = b*b-4*a*c; if (a==0) cout <<"Ecuatia de gradul 1"; else { delta=b*b-4*a*c; if(delta >= 0) { cout<<"Radacini reale: "; x1=(-b+sqrt(delta))/(2*a); x2=(-b-sqrt(delta))/(2*a); cout<<"x1 = "<<x1<<" x2 = "<<x2; } else { cout<<"Radacini complexe :"; delta=-delta; real=-b/(2*a); img=sqrt(delta)/(2*a); cout<<"x1 = "<<real<<" + i*"<<img<<"\n"; cout<<"x2 = "<<real<<" - i*\n"<<img; } } break; case 4 : cout <<"Felicitari , ai ales 'Progresii' , acum va trebui sa alegi tipul de progresie\n"; reset: cout <<"a)Progresii aritmetice\n"; cout <<"b)Progresii geometrice\n"; cout <<"Alege cu 'a' sau 'b': ";cin>>choise; if (choise == 'a') { cout <<"Ai ales progresiile aritmetice , poti da sirul de numere\n"; vector<float> sir; cout <<"Adauga sirul : [apasa 0 cand ai terminat, orice alt tip de caracter va fi ignorat]\n"; do { cin >>input; prog = atoi(input.c_str());// transformam in numar(daca in input e un sir de caractere, chiar si urmat de cifre, functia va returna 0) if(prog == 0) //prog = - 1; continue; // iesim daca s-a introdus un sir de caractere sir.push_back(prog); }while (input != "0"); int dif = 0; int difVeche = 0; bool first = true; bool ok = false; for(int i = 1; i < sir.size();i++) { if(first) { dif = sir - sir[i - 1]; difVeche = dif; first= false; continue; } dif = sir - sir[i - 1]; if(dif != difVeche) { cout << "Sirul nu este in progresie aritmetica." << endl; ok = false; break; } ok = true; if(ok) cout << "Sirul este in progresie aritmetica cu ratia " <<dif<< endl; cout <<"Sirul are " <<sir.size()<< " elemente\n"; cout <<"Doresti sa calculezi suma primilor n termeni? [Y/N] \n"; choise = getch(); if (choise == 'n') goto reset; else cout <<"Ce termen doresti sa calculezi? ";cin>>test; test1=sir[0]+(sir.size()-1)*dif; cout <<"Termenul " <<test<< " este egal cu " <<test1; break; } } if (choise == 'b') { cout <<"Ai ales progresiile geometrice , poti da sirul de numere\n"; vector<float> sir; cout <<"Adauga sirul : [apasa 0 cand ai terminat, orice alt tip de caracter va fi ignorat]\n"; do { cin >>input; prog = atoi(input.c_str());// transformam in numar(daca in input e un sir de caractere, chiar si urmat de cifre, functia va returna 0) if(prog == 0) //prog = - 1; continue; // iesim daca s-a introdus un sir de caractere sir.push_back(prog); }while (input != "0"); int q = 0; int q1 = 0; bool first = true; bool ok = false; for(int i = 1; i < sir.size();i++) { if(first) { q = sir / sir[i - 1]; q1 = q; first= false; continue; } q = sir / sir[i - 1]; if(q != q1) { cout << "Sirul nu este in progresie geometrica." << endl; ok = false; break; } ok = true; if(ok) cout << "Sirul este in progresie geometrica cu ratia " <<q<< endl; cout <<"Sirul are " <<sir.size()<< " elemente\n"; cout <<"Doresti sa calculezi suma primilor n termeni? [Y/N] \n"; choise = getch(); if (choise == 'n') goto reset; else cout <<"Ce termen doresti sa calculezi? ";cin>>test; float a=pow(q , test-1); //bn = b1·qn-1 test2=sir[0]*a; cout <<"Termenul " <<test<< " este egal cu \n" <<test2; break; } } break; case 5 : cout <<"Felicitari ai ales 'cmmdc'\n"; cout<<"a=";cin>>w; cout<<"b=";cin>>z; while(w!=z) if(w> w=w-z; else z=z-w; cout<<"Cmmdc : "<<z; break; default : cout <<"Nu exista aceasta optiune";} goto restart; getchar(); cin.ignore(cin.rdbuf()->in_avail() +1); return 0; }