Problema la insert in tabel

[soimuletzu1]

<form method="post" action="adauga.php">
	     <table cellpadding="4" cellspacing="0">
		 <tr>
		   <td>Server-Name:</td>
		   <td><input type="text" name="name" size="30" /></td>
		 </tr>
		 <tr>
		   <td>Game:</td>
		   <td><input type="text" name="game" size="2" maxlength="2" value="cs"></td>
		 </tr>
		 <tr>
		   <td>Server IP:</td>
		   <td><input type="text" name="ip" size="30" /></td>
		 </tr>
		 <tr>
		   <td>Server Port:</td>
		   <td><input type="text" name="port" size="30" /></td>
		 </tr>
		 <tr>
		   <td>Server Query:</td>
		   <td><input type="text" name="query" size="30"  /></td>
		 </tr>
		 <tr>
		   <td> </td>
		   <td><input type="submit" value="ADAUGA" /></td>
		 </tr>
		 </table>
		 </form>

<?php

if (isset($_POST['name']) && isset($_POST['game']) && isset($_POST['ip']) && isset($_POST['port']) && isset($_POST['query'])) {
  // Se filtreaza datele pt. eliminare posibile spatii exterioare si tag-uri
  $_POST = array_map("trim", $_POST);
  $_POST = array_map("strip_tags", $_POST);

  // Se verifica daca "magic_quotes_gpc()" este setat ON
  // Daca e ON, se aplica stripslashes() pentru a nu se adauga de 2 ori '\' cand va fi aplicat "mysql_real_escape_string()"
  if(get_magic_quotes_gpc()) { $_POST = array_map("stripslashes", $_POST); }

  // Se verifica daca au fost completate corect toate campurile
  // Daca au fost completate le preia in variabile, in caz contrar seteaza o variabila tip Array cu mesaj de eroare

  // Verifica daca Numele are cel putin 5 caractere si maxim 50
  if(strlen($_POST['name'])>5 && strlen($_POST['name'])<50) $name = $_POST['name'];
  else $eroare[] = 'Error Name : 5 and 50 characters';

  // Verifica daca GAME are cel putin 2 si cel mult 3
  if(strlen($_POST['game'])>1 && strlen($_POST['game'])<3) $game = $_POST['game'];
  else $eroare[] = 'Error Game : 2 and 3 characters';

    // Ip intre 5 si 25 de caractere
  if(strlen($_POST['ip'])>5 && strlen($_POST['ip'])<25) $ip = $_POST['ip'];
  else $eroare[] = 'Error IP : 5 and 25 characters';

    // Verifica daca Portul are cel putin 5 caractere si maxim 6
  if(strlen($_POST['port'])>4 && strlen($_POST['port'])<6) $port = $_POST['port'];
  else $eroare[] = 'Error Port : 5 and 6 characters';

      // Verifica daca Query are cel putin 5 caractere si maxim 6
  if(strlen($_POST['query'])>4 && strlen($_POST['query'])<6) $query = $_POST['query'];
  else $eroare[] = 'Error Query : 5 and 6 characters';

  if (!isset($eroare)) {

      $username="user";
      $password="user";
      $database="test";
      $localhost = "localhost";
	  $con = mysql_connect("$localhost","$username","$password");
if (!$con)
  {
  die('Nu sa putut conecta la baza de date: ' . mysql_error());
  }
  mysql_select_db($database, $con);

  // Se aplica functia de filtrare mysql_real_escape_string()
      $name = mysql_real_escape_string($name);
      $game = mysql_real_escape_string($game);
      $ip = mysql_real_escape_string($ip);
	  $port = mysql_real_escape_string($port);
	  $query = mysql_real_escape_string($query);


// Acum se adauga mai in siguranta aceste date in MySQL
    $sql = "INSERT INTO `ws_a96_phgstats` (`name`, `game`, `ip`, `port`, `query`) VALUES ('$name', '$game', '$ip', '$port', '$query')";
	if (mysql_query($sql, $conn)) {
	  $mesaj = '<font color="blue">Serverul a fost adaugat</font>';
	  $name = '';  $ip = '';
	}
    else $mesaj = '<font color="red">Serverul nu a putut fi adaugat '. mysql_error(). '</font>';

	mysql_close($conn);
  }
  else $mesaj = '<font color="red">'. implode('<br />', $eroare). '</font>';
}

echo $mesaj;    
?> 

am urmatorul cod care imi insereaza intr-un tabel campurile de mai sus ... da primesc o eroare cand il, rulez :

Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in C:\xampp\htdocs\adauga.php on line 87

Warning: mysql_close(): supplied argument is not a valid MySQL-Link resource in C:\xampp\htdocs\adauga.php on line 93
Serverul nu a putut fi adaugat 

Stiti careva unde am gresit???

[tiodr]

posteaza exact linia 87 si 93 te rugam

daca linia 87 este mysql_query($sql, $conn) atunci incearca mysql_query($sql)

daca linia 93 este mysql_close($conn) atunci incearca mysql_close($con)

Edited March 31, 2011 by tiodr

[soimuletzu1]

linia 87 : if (mysql_query($sql, $conn)) {

linia 93 : mysql_close($conn);

ms pentru raspunsul rapid. merge super acum ...

[tiodr]

in loc de mysql_query($sql, $conn) incearca mysql_query($sql)

in loc de mysql_close($conn) incearca mysql_close($con)

[soimuletzu1]

Ca sa nu mai fac un nou topic voi intreba tot aici !

img=http://img140.imageshack.us/img140/5290/photo1twc.jpg

Cum as putea sa separ partea <form> de partea cu imagini dar totusi sa le am in acelasi fisier? Adica partea de jos de la imagine + codurile bb/html sa apara dupa ce dau Check server , ms