Transform a string into a 32-bit number

[bogdanvaduva]

Salut,

 

Am intalnit urmatoarea problema. Primesc un char * care reprezinta un ip. Ideea e ca eu trebuie sa compar mai multe ip-uri, dar, trebuie ca ele sa fie transformate in int32_t, adica numere pe 32 de biti.

 

Are cineva idee cum se face asta? Initial am incercat ceva de genul asta

 

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdarg.h>
 

 int main (){

char * buffer;
int sum = 0, i;
buffer = (char*)malloc(100*sizeof(char));

scanf("%s", buffer);

int32_t x;

x = (int32_t)buffer;

printf("%zu\n", x);

 }

Am mai incercat la afisare sa fac cu %lo dar nu am obtinut nimic. Are cineva idee :D?

[kznamst]

http://stackoverflow.com/questions/8167257/right-way-to-convert-char-number-to-int32-t
 

<inttypes.h>
int32_t i;
sscanf(str, "%"SCNd32, &i);

 

Edited April 29, 2016 by kznamst

[Byte-ul]

http://stackoverflow.com/questions/10283703/conversion-of-ip-address-to-integer