dsp77 Posted August 3, 2011 Report Share Posted August 3, 2011 Buna Dimineata.Un test de IQ pe care l-am dat acum ani multi si trebuia rezolvat in 60 de secunde. Daca doriti puteti nota timpul pentru comparatia cu alti membri.Avem urmatoarele grupe numere:1 1 1 = 62 2 2 = 63 3 3 = 64 4 4 = 65 5 5 = 66 6 6 = 67 7 7 = 68 8 8 = 69 9 9 = 610 10 10 = 6Folositi orice tip de de calcul matematic, practic orice fara adaugarea altor numere pentru ca rezultatul final sa fie intotdeauna 6.Stiu ca exista marele Google dar incercati sa nu fiti tentati.Sa luam un exemplu simplu: 2 2 2 = 6, rezolvare: 2+2+2=6.Rezolvare placuta. Quote Link to comment Share on other sites More sharing options...
Skiddie Posted August 3, 2011 Report Share Posted August 3, 2011 Sa inteleg ca trebuie folosite doar acele 3 cifre nu putem adauga mai multe nu? ex 1111?3x3-3=64laa2a-(4+4)=65:5+5=66x6:6=67-7:7=6(9+9):radical9=6Mai ramane cu 8. Quote Link to comment Share on other sites More sharing options...
dsp77 Posted August 3, 2011 Author Report Share Posted August 3, 2011 (edited) 4laa2a-(4+4)=6 nu este validnu poti folosi la putere pt ca implica un numar. Strict doar cele 3 le puteti folosi.Felicitari pentru restu:)mai raman:1 1 14 4 48 8 89 9 910 10 10 Edited August 3, 2011 by dsp77 Quote Link to comment Share on other sites More sharing options...
co4ie Posted August 3, 2011 Report Share Posted August 3, 2011 8-radical(radical(8+8))=6 sau 8!!/(8*8)=6 (!! e dublu factorial)(radical(9*9/9))!=6 si 9 a lui Skiddie e corect...4 + 4 – radical4= 62+2+2=61 1 1 poate fi facut cu operatorii de incremetare ... ++1 + ++1 + ++1=6 Quote Link to comment Share on other sites More sharing options...
Usr6 Posted August 3, 2011 Report Share Posted August 3, 2011 (1+1+1)!=610+10+10=6, 10 in binar=2 Quote Link to comment Share on other sites More sharing options...
demon_zone Posted August 3, 2011 Report Share Posted August 3, 2011 dont forget the logarithms Quote Link to comment Share on other sites More sharing options...
dsp77 Posted August 3, 2011 Author Report Share Posted August 3, 2011 felicitari mai ramane grupa de 10 Quote Link to comment Share on other sites More sharing options...
demon_zone Posted August 3, 2011 Report Share Posted August 3, 2011 (edited) logarithms dude... infineziceti-mi la 11 11 11 = 6. Desi ma indoiesc sa existe vre-o rezolvare. Edited August 3, 2011 by demon_zone LOG is the word Quote Link to comment Share on other sites More sharing options...
dsp77 Posted August 3, 2011 Author Report Share Posted August 3, 2011 grupa de 10 se poate rezolva fara log Quote Link to comment Share on other sites More sharing options...
demon_zone Posted August 3, 2011 Report Share Posted August 3, 2011 (edited) (rad(10-(10/10)))!=6still, 11 anyone? Edited August 3, 2011 by demon_zone indeed it can. also, try the LN Quote Link to comment Share on other sites More sharing options...
dsp77 Posted August 3, 2011 Author Report Share Posted August 3, 2011 felicitari tuturor Challenge terminat cu un forum super:D@demon_zone ai raspunsul la 11 sau doar curios? Quote Link to comment Share on other sites More sharing options...
demon_zone Posted August 3, 2011 Report Share Posted August 3, 2011 just curiousdar pun la bataie un luptator de sumo ca nu are rezolvare Quote Link to comment Share on other sites More sharing options...
em Posted August 3, 2011 Report Share Posted August 3, 2011 (11!)/(sqrt(11*11)) = 6Ai pierdut un lupt?tor de sumo! Nu pare a fi corect. Quote Link to comment Share on other sites More sharing options...
co4ie Posted August 3, 2011 Report Share Posted August 3, 2011 (11!)/(sqrt(11*11)) = 6 nu e corect... si nici eu nu cred ca exista rezolvare pt 11... pt 10 am avut si eu aceeasi rezolvare ca si demon_zone ! pt 11 de o juma de ora incerc si nu-mi ies decat ochii... Quote Link to comment Share on other sites More sharing options...
em Posted August 3, 2011 Report Share Posted August 3, 2011 Am voie a?a?11*11-11=6(baza 2/baza 10) Quote Link to comment Share on other sites More sharing options...
em Posted August 3, 2011 Report Share Posted August 3, 2011 Opera?ii matematice, em. Bazele sunt deja logice din câte ?tiu.Atunci fac a?a(1+1+1)!*1*1*1=6 Quote Link to comment Share on other sites More sharing options...
em Posted August 3, 2011 Report Share Posted August 3, 2011 Dap. [sqrt 11]*[sqrt 11]-[sqrt 11]=3*3-3=6Unde [] - parte întreag?. Quote Link to comment Share on other sites More sharing options...
