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XgaMeR

Aegis Crypter 3.0

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Posted

Lemme Help You Guys :P

Solve the value for x

x²+130x-5775=0

(x-35)(x+165)=0

(x-35)=0 and (x+165)=0

x=35 and x=-165

Convert the values of x to base64

x=35 -> base64 -> MzU=

x=-165 -> base64 -> LTE2NQ==

So the password is either MzU= or LTE2NQ== . In this case, the correct password is MzU=

Enjoy

HACKOLOGY

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