Hertz Posted August 7, 2009 Report Share Posted August 7, 2009 numar = ((17 la puterea 39) la puterea 11)Ia fiecare a 33-a cifra a lui numar , incepand cu prima si concateneaza-le.Care e numarul final?Simplu,bafta:) Quote Link to comment Share on other sites More sharing options...
CyberWolf08 Posted August 8, 2009 Report Share Posted August 8, 2009 Cifrele cu ordinul divizibl cu 33 sunt 496883104146177, iar suma lor e 69.iar numarul este 728764604717569380918100365856062469000193424947503758338341096686996857544674362272347240426271029642988418205160372335284759784597854147593648871858097274405592779889038847476635050174799866232012301434410796898542809249563904637123246883888343967063554848246342020278889116481636463252182831519420559906799180791086985957341197127783330565772564242651403912456455317933419062751330828700987778645214725045780084668671936673752128478286140806951581228924388701768931419905595306419093162717560756925359266275186144493274175697Traiasca WolframAlpha Quote Link to comment Share on other sites More sharing options...
Hertz Posted August 8, 2009 Author Report Share Posted August 8, 2009 Corect , traiasca. Quote Link to comment Share on other sites More sharing options...
Zatarra Posted September 13, 2009 Report Share Posted September 13, 2009 Ceva asemanator cu 5^5^5^5...5^5^5 abc..xyz. Era mai interesant programul meu de acolo decat WolframAlpha. oricum in cazuri extreme ii si WolframAlpha extrem de bun Quote Link to comment Share on other sites More sharing options...
