Password Generator

[bybo]

Salut RST astazi vreau sa va prezint un script care genereaza o parola random

Link Download:

 http://www.mediafire.com/downloa?d/2lnchenat14la0h/Password+genera?tor.zip 

Source Code:

EDIT:

 
import string
import random
def id1(size=3, chars=string.ascii_uppercase + string.digits + string.ascii_lowercase):
        return ''.join(random.choice(chars) for c in range(size))

def id2(size=5, chars=string.ascii_uppercase + string.digits + string.ascii_lowercase):
        return ''.join(random.choice(chars) for c in range(size))

def id3(size=8, chars=string.ascii_uppercase + string.digits + string.ascii_lowercase):
        return ''.join(random.choice(chars) for c in range(size))


def id4(size=12, chars=string.ascii_uppercase + string.digits + string.ascii_lowercase):
        return ''.join(random.choice(chars) for c in range(size))


print """Welcome to PassCreator v1.0 by Puka
Here u can select how many caracters your password gonna have ex: 5 Char.=1xgf5
--------------------------------------------------------------------------------
1.Password with 3 characters
2.Password with 5 characters
3.Password with 8 characters
4.Password with 12 characters
"""
c = input ("Type your option(1/2/3/4): ")
password = ""
if c == 1:
        password = id1()
        print password
if c == 2:
        password = id2()
        print password
if c == 3:
        password = id3()
        print password
if c == 4:
        password = id4()
        print password

m = raw_input("Do you wish to save the password?(y/n)")
print m
if m == 'y' or m == 'Y':
        with open ("passlog.txt", "a") as file:
                file.write('Your generated password is : ' + str(password) + "\n")

In mare parte e facut de manutele mele dar si cu mult ajutor din partea lui Psiho, mrgrj, gecko si inca un baiat

Edited November 14, 2015 by bybo

[MrGrj]

Ce-ai ma ?

Eu nu te-am ajutat niciodata sa convertesti un string iar in string:

AKA:

m = [B]raw_input[/B]("Do you wish to save the password?(y/n)") # asta e deja string (ti-am explicat de 10 ori cel putin, mi-e martor tot chatu')

Si acum pui conditite (ca sa fii tu sigur ca e string):

if [B]str[/B](m) == 'y' or [B]str[/B](m) == 'Y'

Spor la invatat in continuare though

PS: In python 3.x raw_input() devine input() iar input()-ul din 2.x a fost removed.

Edited September 24, 2015 by MrGrj

[Ganav]

Salut RST astazi vreau sa va prezint un script care genereaza o parola random

Link Download:

 http://www.mediafire.com/downloa?d/2lnchenat14la0h/Password+genera?tor.zip 

Source Code:

 import string
import random
def id1(size=3, chars=string.ascii_uppercase + string.digits + string.ascii_lowercase):
        return ''.join(random.choice(chars) for c in range(size))

def id2(size=5, chars=string.ascii_uppercase + string.digits + string.ascii_lowercase):
        return ''.join(random.choice(chars) for c in range(size))

def id3(size=8, chars=string.ascii_uppercase + string.digits + string.ascii_lowercase):
        return ''.join(random.choice(chars) for c in range(size))


def id4(size=12, chars=string.ascii_uppercase + string.digits + string.ascii_lowercase):
        return ''.join(random.choice(chars) for c in range(size))


print """Welcome to PassCreator v1.0 by Puka
Here u can select how many caracters your password gonna have ex: 5 Char.=1xgf5
--------------------------------------------------------------------------------
1.Password with 3 characters
2.Password with 5 characters
3.Password with 8 characters
4.Password with 12 characters
"""
c = input ("Type your option(1/2/3/4): ")
password = ""
if c == 1:
        password = id1()
	print password
if c == 2:
        password = id2()
	print password
if c == 3:
        password = id3()
	print password
if c == 4:
        password = id4()
	print password

m = raw_input("Do you wish to save the password?(y/n)")
print str(m)
if str(m) == 'y' or str(m) == 'Y':
	with open ("passlog.txt", "w") as file:
		file.write('Your generated password is : ' + str(password))

In mare parte e facut de manutele mele dar si cu mult ajutor din partea lui Psiho, mrgrj, gecko si inca un baiat

Se putea realiza mult, mult mai simplu in bash:

export lungime_parola=20
export nr_parole=1
cat /dev/urandom | tr -dc 'a-zA-Z0-9-_!@#$%^&*()_+{}|:<>?=' | fold -w "$lungime_parola" | head -n "$nr_parole"

si vezi ca generatoarele random din bibliotecile implicite ale limbajelor de programare nu au o entropie buna; adica reproduc secvente de biti care pot fi prezise.

[dancezar]

password=""
if c == 1:
        password = id1()
	print password
if c == 2:
        password = id2()
	print password
if c == 3:
        password = id3()
	print password
if c == 4:
        password = id4()
	print password

Toata asta poate fi scrisa mai comprimat asa:

functii={1:id1,2:id2,3:id3,4:id4}
try:
	print functii[c]()
except KeyError:
	print "Nu exista alegerea:"+str(c)

[bybo]

da mi-am dat si eu seama ca putea fi scrisa mai comprimat dar sunt incepator in python si nu stiu bash sau alte chestii stiu doar putin din python so multumesc pentru explicatii