begood

@ TheTime : metoda asta am folosit-o si eu in clasa a 9-a. LE : *asemanatoare chiar daca la nivel cuantic exista anumite probabilitati de a se intampla acele evenimente, asta nu inseamna ca ele nu se vor intampla in mod complet random, fara sa existe vreo metoda sa prezici urmatorul pas.

Random, but not by chance: A quantum random-number generator for encryption, security na asta e random.

n-am gasit nimic legat de o diploma, dar poti urmari Udacity - Educating the 21st Century pentru cursuri care se termina cu o diploma.

So basically what I want is this : to get a RST simple figure from an even more simpler structure that has rules like the Game of Life. Now the problems that arise are this : 1. What shape should be the initial one. 2. How to compute the rules. 3. How to make rules so that the logo is generated from a single point with a minimum number of steps. 4. How to determine the initial figure so that given a very simple (the absolute simple) rule it will eventually evolve into the logo. Read more: http://a2480f25.blogspot.com/2012/02/reversing-patterns-in-game-of-life-no.html#ixzz1n1OphQ4a Under Creative Commons License: Attribution Non-Commercial Share Alike puteti raspunde in romana sau engleza.

Am dat si de cursurile de la MIT (MITx) Circuite si Electronica (MITx 6.002) Presimt o revolutie a universitatilor de prestigiu care isi ofera materialele online la zeci de mii de participanti. Postati unde va inscrieti sa aflam si noi !

Postati la ce va inscrieti, sa vedem si noi de ce e interesata lumea.

Da, multe au fost amanate, pe diverse motive. Sunt literalmente zeci de mii de oameni ce s-au inscris, iar cum ei au material video, inseamna ca le trebuie o banda larga pentru a satisface toti clientii. Model Thinking e live spre exemplu.

Sunt 11 cursuri gratuite de informatica predate online de profesori de renume de la Universitatea Standford. 1. Informatica 1 la 1 (101) 2. Inteligenta Artificiala - Machine Learning 3. Software ca si serviciu [software as a Service (SaaS)] - Cloud Computing 4. Interactiune Om-Computer 5. Procesarea Limbajului Natural 6. Teoria Jocurilor 7. Modele Probabilistice Grafice 8. Criptografie 9. Designul si analiza Algoritmilor 10. Securitatea Computerelor 11. Cum vad Computerele (Computer Vision) Mai sunt si alte cursuri : Anatomie Ingineria Cladirilor Teoria Informatiei Gandirea in Modele - Patterns Eu m-am inscris la toate, sa vad despre ce e vorba.

Ceva underground de dimensiuni asemanatoare exista ? As plati subscriptie pentru acces.

https://www.eff.org/https-everywhere

vand eu iphone 4 ieftin oriunde in tara, e aproape nou. pm me.

Ai putea sa instalezi un wifi repeater pe fiecare cladire cu aprobarea administratorilor (cateva beri). Cred ca iesi mai ieftin daca iti iei net prin satelit.

prostia, in top ! ce cacat promovati idiotii ?

Common sense (and your irrational compulsion to, you know, keep your job) says drinking at work—or working when you're groggy—are bad news. But as Wired's Jonah Lehrer points out, recent studies reveal that being sleeping and/or drunk is great for creativity. Here's why: When you're solving problems, your brain is built to shine a spotlight on what it considers relevant, ignoring ideas and connections that aren't likely solutions to your problem. This is a good thing, since without that focus your mind would be flooded with loads of irrelevant information when attempting to solve a simple task, and for what Lehrer calls standard analytic problems, that kind of focus is essential. When it comes to creative problem solving, however, your brain does better without that focus. To demonstrate, researches presented two groups—one of which consisted of patients with severe attention deficits caused by damage to their prefrontal lobes—with puzzles. When presented with the more creatively challenging problem, the patients suffering from attention deficits performed significantly better: In this case, only 43 percent of normal subjects were able to solve the problem. The patients who couldn't pay attention, however, had an 82 percent success rate. What accounts for this bizarre result? Why does brain damage dramatically improve performance on a hard creative task? ...The patients with a severe cognitive deficit... can't restrict their search. They are forced by their brain injury to consider a much wider range of possible answers. And this is why they're nearly twice as likely to have a breakthrough. A second, similar study presented creative and analytic problems to groggy students, and a third did the same with drunk students. Like the patients with pre-frontal lobe damage, the tired and drunk students consistently performed better on creative problems. Lehrer sums it up nicely The stupor of alcohol, like the haze of the early morning, makes it harder for us to ignore those unlikely thoughts and remote associations that are such important elements of the imagination. So the next time you are in need of insight, avoid caffeine and concentration. Don't chain yourself to your desk. Instead, set the alarm a few minutes early and wallow in your groggy thoughts. And if that doesn't work, chug a beer. Why Being Sleepy and Drunk Are Great for Creativity | Wired Science | Wired.com via lifehacker

ce n-as da, dar doar pentru ocazia asta, sa traiesc in SUA, langa centrul NSA.

fu*ut de tinkode ?

cum ai ajuns la noi ?

https://www.accessnow.org/policy-activism/press-blog/acta-protest-feb-11 20.000 in bucuresti

m-am lasat o perioada buna. am slabit din cauza asta, luna viitoare ma reapuc.

verfica cineva (bruteforce/demonstratie matematica) daca gcd(fib(a,)==fib(gcd(a,) ? ar fi bine de stiut sigur. LE: am gasit-o. nu stiam de ea. bravos !

poate poti prezice divizorii in functie de pozitie.

acum demonstreaza ca-s mereu prime intre ele.

plm dai un ceil acolo. true, diferenta e maricica. dar sunt sigur ca se poate optimiza cu putin efort.

#include <stdio.h> #include <math.h> #include <conio.h> long gcd(long a, long { for (long r = a % b; r != 0; a = b, b = r, r = a % ; return b; } int main (){ float phi=(sqrt(5)+1)/2; long a,b; int x,y; printf("Primul numar: "); scanf("%d",&x); printf("\nAl doilea numar: "); scanf("%d",&y); a=(long)((pow(phi,x) - pow(-phi,-x)) / sqrt(5)); b=(long)((pow(phi,y) - pow(-phi,-y)) / sqrt(5)); printf("\nf(%d)=%lu\nf(%d)=%lu",x,a,y,; printf("\nCMMDC(f(a),f(= %lu",gcd(a,); printf("\nUnde f(a) este numarul din sirul fibonacci de pe pozitia a."); getch(); return 0; } @skull ce zici de metoda mea ?