ZeroCold Posted December 2, 2009 Report Share Posted December 2, 2009 Calculeaz? num?rul care trebuie ad?ugat la toate cele patru membre la adunare a?a încât formula s? aprobe.X - numarul care trebuie adaugat 655X + 399X + 407X = 1487XX=? Quote Link to comment Share on other sites More sharing options...
daatdraqq Posted December 2, 2009 Report Share Posted December 2, 2009 nu da cu niciun numar 1487x ,cel mai mult poate fi 14637 .Sau numarul poate fi format si din 2 cifre? 1 Quote Link to comment Share on other sites More sharing options...
begood Posted December 2, 2009 Report Share Posted December 2, 2009 e vorba doar de ultima cifra && ecuatia ta.Uc(3x)=xplm ai si gresit enuntul. Quote Link to comment Share on other sites More sharing options...
demon_zone Posted December 2, 2009 Report Share Posted December 2, 2009 655X + 399X + 407X = 1487Xnu are cum, ca 5+9+7 nu ta ultima cifra 75+9+7 da 21,ceea ce inseamna ca x+x+x sa dea intre 60 - 69,ca sa dam pe 6 mai departedaca ati priceput ceva... Quote Link to comment Share on other sites More sharing options...
begood Posted December 2, 2009 Report Share Posted December 2, 2009 0->0;1->3;2->6;3->9;4->2;5->5;6->8;7->1;8->4;9->7;solutie ar fi 0 si 5;daca e 0 => 14610 != 14870daca e 5 => 14625 != 14875 Quote Link to comment Share on other sites More sharing options...
Fitty Posted December 2, 2009 Report Share Posted December 2, 2009 Da, e imposibil. Halal exercitiu, halal carti. Quote Link to comment Share on other sites More sharing options...
demon_zone Posted December 2, 2009 Report Share Posted December 2, 2009 staimai e o fazanoi am luat x ca cifrada daca il luam ca numar din mai multe cifre?dar ar trebui sa fie de 2 ori x... Quote Link to comment Share on other sites More sharing options...
loki Posted December 2, 2009 Report Share Posted December 2, 2009 am incercat.Nu are solutie indiferent.x+x+x=x - x=0 sau 5xy+xy+xy=xy - xy=00... Quote Link to comment Share on other sites More sharing options...
begood Posted December 2, 2009 Report Share Posted December 2, 2009 @ demon_zone daca ar fi ce zici tu atunci :655*X + 399*X + 407*X = 1487*X => 1461*X=1487*X iar de aici X=0. Quote Link to comment Share on other sites More sharing options...
030893 Posted December 2, 2009 Report Share Posted December 2, 2009 pai vine1461x=1487x1461x-1487x=0 -26x=0 --> x= 0: (-26) orice nr impartit la 0 da 0 deci x=0 Quote Link to comment Share on other sites More sharing options...
demon_zone Posted December 2, 2009 Report Share Posted December 2, 2009 bravo einsteinx=0atunci:6550 + 3990 + 4070 = 14870nu?@begood655*X + 399*X + 407*X = 1487*Xma refeream la :655XX + 399XX + 407XX = 1487XXsau 655XXX + 399XXX + 407XXX = 1487XXXdar tot degeaba,nu are cumimposibil Quote Link to comment Share on other sites More sharing options...
Marian Posted December 2, 2009 Report Share Posted December 2, 2009 bravo einsteinma refeream la :655XX + 399XX + 407XX = 1487XXsau 655XXX + 399XXX + 407XXX = 1487XXXdar tot degeaba,nu are cumimposibilStau de 2 ore... are macar un rezultat? Quote Link to comment Share on other sites More sharing options...
demon_zone Posted December 2, 2009 Report Share Posted December 2, 2009 nu caxxxx din capatu numerelor trebe sa fie acelasi peste toex:daca 6789 e in capatu lui 655, tot 6789 trebuie sa fie si in capatu celorlalte...cel putin asa am inteles euX - numarul care trebuie adaugat nu e655X + 399a + 407y = 1487zsper ca ati priceput ceva... Quote Link to comment Share on other sites More sharing options...
ZeroCold Posted December 3, 2009 Author Report Share Posted December 3, 2009 (edited) X, in imagine e casuta, nu am pus de la inceput imaginea pt ca eram pe telefon , si nu puteam.Trebuie sa gasiti un numar, care sa se potriveasca peste tot (trebuie sa fie acelasi numar peste tot).De ex:6552+3992+4072=14872Sau 65534+39934+40734=148734sau6552012+3992012+4072012=14872012:D:DProblema am luat-o de la un concurs de mate si logica, are rezolvare .----------------------------------------------EDIT:Eu ma chinui de 3 zile sa il rezolv Poate sa faca cineva un programel C++/C/pascal, nu conteaza ce limbaj care sa sa puna fiecare cifra, de la 1 la 1000, in locul lui x si sa testeze daca este egal cu 1487X ?Cred ca intelegeti ce am spus X poate avea n cifre :D:D, asta face ex ff greu, daca era doar 1 cifra nu avea rost sa il mai pun aici Edited December 3, 2009 by ZeroCold Quote Link to comment Share on other sites More sharing options...
demon_zone Posted December 3, 2009 Report Share Posted December 3, 2009 okpai zi asa, ca x are mai multe cifrex este suma unor cifre (de la 1 la 9 ) ca sa dea intre 60 si 69acum sunt in graba,am sa fac rezolvarea mai diseara Quote Link to comment Share on other sites More sharing options...
begood Posted December 3, 2009 Report Share Posted December 3, 2009 #include <iostream.h>#include <math.h>int nrcifre(unsigned long a) { unsigned long aux=0; while(a!=0) { a/=10; aux++; } return aux; }int verif(unsigned long a) { int x=pow(10,nrcifre(a)); if (a==(a*3)%x) return 1; return 0; }void main() { unsigned long n; do{cout<<"Dati orice n < 4 miliarde \nn=";cin>>n;}while(n>4000000000); for (unsigned long i=5;i<n;i++) if (verif(i)) cout<<i<<" "; }//sursa nesecurizata pentru borland c++ 3.15,50,500,5000,... a(y)=5*10^y, y apartine lui {0,1,2,... infinit}verificati voi care merg...eu garantez ca nu are solutie.le..ah am uitat ca si 0 e solutie preliminara la sir...le2: prescurtat :if (x==(x*3)mod(10^nrcifre(x)) && 655x+399x+407x==1487x)return 1.le3: mi-a venit o idee, totusi s-ar putea sa fie o solutie le4: sunt 100% sigur ca nu are solutie deoarece :0: 146105: 1462550: 146250500: 14625005*10^z: 14625*10^z.so ecuatia pentru orice a(z)>0 arata asa : 14625*10^z. (a(z) =X)rezultatul 1487x nu exista deoarece toate numerele vor incepe cu 14625.=>problema nu are solutii intregi. Quote Link to comment Share on other sites More sharing options...
loki Posted December 3, 2009 Report Share Posted December 3, 2009 problema cred ca tine de logicaPresupunand ca x are oricate cifre, luam cel mai mare x=999999..... la limita tinde la 1000000...Hai sa zicem ca X e o zecimala, e tot una (impartim ecuatia cu 10^y).655,x+399,x+407,x=1487,xunde 0<=x<=0,9999....<1Daca adaugam 1 la termeni656+400+408=1464 este mai mic (mult mai mic) decat 1488Concluzie: nu are rezolvare matematica prin lipirea unui x, nu merge prin incercari.Deci lasati matematica.Atunci poate tine de un aspect logic sau poate nu are rezolvare in baza 10.Apropo, (655+399+408)/3=1461/3=487 .... 1487 ciudat Quote Link to comment Share on other sites More sharing options...
