wildchild Posted May 14, 2012 Report Share Posted May 14, 2012 Deci, stanga sau dreapta? Sau alt raspuns.Si argumente, daca se poate. Quote Link to comment Share on other sites More sharing options...
OnlineHelp Posted May 14, 2012 Report Share Posted May 14, 2012 Stanga, ca asa e. Quote Link to comment Share on other sites More sharing options...
sandabot Posted May 14, 2012 Report Share Posted May 14, 2012 (edited) Deci e fara forta de frecare ?Forta de frecare ajuta yoyo-ul sa se miste spre stanga , dar daca nu exista, singura forta care actioneaza asupra lui este mana cu sfoara deci ce pot spune este ca se misca spre dreapta.//daca gresesc corectati-ma . Edited May 14, 2012 by sandabot Quote Link to comment Share on other sites More sharing options...
secure Posted May 14, 2012 Report Share Posted May 14, 2012 Depinde de suprafata, materialul din care e facut yoyo si de forta cu care este tras. Poate fi stanga, dreapta sau sa se invarta pe loc. Stanga este logic dar numai dupa ce face macar o semirotatie pe loc dupa care inertia il va trimite in sens opus. Dreapta daca ata nu e stransa bine pe yoyo si capatul ei e tras cu putere. Pe loc daca suprafata si materialul permit totusi o minima alunecare. Prea multi factori sunt la mijloc si o poza nu ne da prea multe indicii. Cel mai futut factor e forta cu care se trage de capatul atei. Quote Link to comment Share on other sites More sharing options...
against_modern_football Posted May 14, 2012 Report Share Posted May 14, 2012 depinde de directie:) daca urca e spre dreapta asa cum e desenata forta acum, daca coboara o sa ai in loc de F -F, adica aceeasi forta in directie opusa Quote Link to comment Share on other sites More sharing options...
begood Posted May 14, 2012 Report Share Posted May 14, 2012 (edited) Stanga. No slip == Nu aluneca == Coeficient de frecare la alunecare = 1 => se va roti spre stanga.Coeficientul de frecare la rotire nu este precizat => se presupune strict mai mic decat 1 => se roteste. Daca e 1 nu se va putea clinti din loc. Edited May 14, 2012 by begood Quote Link to comment Share on other sites More sharing options...
staticwater Posted May 14, 2012 Report Share Posted May 14, 2012 (edited) No slip -> nu aluneca-> miscare de rotatie-> se va roti spre stangaFf – forta de frecare: Ff = ?*G= ?*M*g 0 < ? < 1M*a = F – Ff (1)I*? = F*r – Ff*R (2)? = a/R; (3)din (1), (2), (3) poti calcula acceleratia Edited May 14, 2012 by staticwater Quote Link to comment Share on other sites More sharing options...
ionutz15 Posted May 14, 2012 Report Share Posted May 14, 2012 Sta pe loc Quote Link to comment Share on other sites More sharing options...
Maximus Posted May 14, 2012 Report Share Posted May 14, 2012 I like your math / physics, the only problem is that I can't understand it No slip -> nu aluneca-> miscare de rotatie-> se va roti spre stangaFf – forta de frecare: Ff = ?*G= ?*m*g 0 < ? < 1M*a = F – Ff (1)I*E = F*R – Ff*r (2)E = a/R; (3)din (1), (2), (3) poti calcula acceleratia Quote Link to comment Share on other sites More sharing options...
DreptulLaReplica Posted May 14, 2012 Report Share Posted May 14, 2012 (edited) [caterinca] In jos? [/caterinca]Sta pe loc:) din cauza fortelor exercitate din ambele parti care nu ii da voie sa se miste si din cauza razelor:) Edited May 14, 2012 by DreptulLaReplica Quote Link to comment Share on other sites More sharing options...
Gonzalez Posted May 15, 2012 Report Share Posted May 15, 2012 Stanga. -Gonzalez Quote Link to comment Share on other sites More sharing options...