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In this Reverse Engineering and Exploit Development training course, expert author Philip Polstra will teach you about common software vulnerabilities and how to find them, as well as how the vulnerabilities differ between various operating systems. This course is designed for beginners who are looking to get started in security, penetration testing, and reverse engineering. You will start by learning about reversing compiled Windows applications, including using fuzzing, stack overflows, and heap overflows. From there, Philip will teach you how to reverse compiled OS X, Linux, and Android applications. This video tutorial also covers how to find other vulnerabilities, including website and database vulnerabilities. Finally, you will learn about simple exploits, web exploitation, and ARM exploitation. Once you have completed this computer based training course, you will be fully capable of finding vulnerabilities and developing exploits for them. Working files are included, allowing you to follow along with the author throughout the lessons. https://yadi.sk/d/e4JEUKNfg3oUv sursa: https://forum.reverse4you.org/showthread.php?t=1997

// // Dear maintainer: // // Once you are done trying to 'optimize' this routine, // and have realized what a terrible mistake that was, // please increment the following counter as a warning // to the next guy: // // total_hours_wasted_here = 42 // nu e de pe rst, dar

Nu inteleg nimic din codul asta postat. Pune-l si tu pe bpaste cu indentarea corecta. - ai ; dupa while - as face functia lengthOfCollatzSequence de tipul long long - in main() folosesti arg si argv dar nu le folosesti nicaieri - if(length >=x) -> aici aveai nevoie de acolade (ai doua instructiuni) Problema cu time limit exceeded este din cauza faptului ca programul tau, la un moment dat incearca sa calculeze un nr. mai mare de 2^31 - 1. Incearca asa: #include <stdio.h> #include <stdlib.h> int lengthOfCollatzSequence(int n) { unsigned i = 0; while(n != 1) { if(n % 2 == 0) n = n / 2; else n = 3 * n + 1; i++; } return i; } int main() { int a, b, length = 0, x = 0; scanf("%d %d", &a, &b); for(;a <= b; a++) { int l = lengthOfCollatzSequence(a); if(length < l) { length = l; x = a; } } printf("%d", x); } PS: Nu mai ai nevoie de return 0. E un subiect discutat foarte mult in ultimul timp. Compilatorul stie sa il puna singur cand intalneste } din main (in C99 cel putin). Pentru mai multe detalii: http://stackoverflow.com/a/4138710/6165050