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Walkthrough: Facut pe Lubuntu 17.04 1. Descarcam imaginea si verificam daca este integra(cred ca am descarcat-o de trei ori pana sa o iau pe cea buna, in rest descarcam doar thumbnail-ul) deci pasul asta e destul de important. $ md5sum crack_me.jpg c720e708ab375e531bb77dca9dd08d38 crack_me.jpg # Deci e ok 2. Dupa cum observam, in imagine este un lacat cu trei rotite. O deschidem cu un editor hex si cautam sa vedem daca in afara de imagine mai este ceva. Ne uitam sa vedem daca dupa biti FF D9 mai este ceva: PK sa_nu_uitam.jpg Observam ca dupa biti de sfarsit al jpg-ului sunt initialele PK ceea ce inseamna ca avem o arhiva zip.(inițialele lui Phil Katz, creatorul formatului zip). In arhiva observam ca mai este o poza "sa_nu_uitam.jpg" 3. Incercam sa o dezarhivam, dar observam ca ne cere o parola, ne intoarcem la poza initiala si asteptam sa ne vina o idee. Prima idee e sa generam toate codurile posibile pentru acel lacat. Am folosit C++ pt asta(lucrez in el si mi-a fost mai usor): #include <iostream> using namespace std; int main() { char digits[] = "0123456789"; char pass[4]; pass[3] = 0; for( int i = 0; i < 10; i++) { pass[0] = digits[i]; for( int j = 0; j < 10; j++) { pass[1] = digits[j]; for( int z = 0; z < 10; z++) { pass[2] = digits[z]; cout << pass << endl; } } } return 0; } /// Il compilam iar cand il rulam ii redirectionam iesirea intr-un fisier: $ g++ main.cpp -o executabil $ ./executabil >> fisier.txt Se poate face in orice limbaj, aici aveti si ceva in python: https://stackoverflow.com/questions/22214949/generate-numbers-with-3-digits 4. Dupa ce am generat toate numerele e timpul sa trecem la bruteforce. Am folosit fcrackzip + am redenumit imaginea crack_me.zip(am schimbat extensia ca se plangea fcrackzip-ul): $ fcrackzip -D -p fisier.txt -u crack_me.zip 5. Primim confirmarea ca parola este : "PASSWORD FOUND!!!!: pw == 099". Dezarhivam si obtinem o nou imagine. 6. Repetam pasul doi si observam ca si aceasta imagine e tot o arhiva cu parola. Prima idee care mi-a venit in minte a fost sa incerc sa pun coordonatele boturilor avioanelor(cei care au jucat avioane stiu ca daca nimeresti botul avionul e pierdut). Asa ca am luat-o in ordine: avionul gri, cel albastru si cel portocaliu -> c2c8j5. Asta e parola. 7. Obtinem un fisier text "acum_e_acum.txt" cu mai cuvinte, fiecare pe o singura linie. La inceput am incercat Caesar's Cipher, dar fara vreun rezultata. Dupa ce am cerut un hint, mi s-a zis sa numar literele de pe fiecare linie. Deci vom avea: d o v g d u 6 - > F p j c d r 5 - > E a j i u g j s t k x r y 12 -> L c l f t c c p c g 9 -> I o l q 3 -> C z w w m y i l k a 9 -> I c o e g a p i c p f q h t j w x i p r t 20 -> T d 1 -> A e z v q o x b h d r g g d l t f z r 18 -> R n s v p m s r t l 9 -> I z m j j b 5 -> E p s r o g e m h p d d u v p k y y s a 19 -> S b e m p y l h o m m f w a j a o p c o s 20 -> T e j r q t u i u e 9 -> I g x m c o f a n b o q q w q u y t l i s a 21 -> U q b e g h l f b i f y o j k 14 -> N b y v a l i b t i h r z i c g l n t 18 -> R s h r f v i u h d g p q g s k 15 -> O g x c v s g q s u k v u s 13 -> M c 1 -> A z k o j u v l c l z w u h o 14 -> N k 1 -> A x i g c 4 -> D l c g b e 5 -> E x j t g r e i v d i r d s g d j t k j t g q 22 -> V n 1 -> A x k j k b c c u a j c p s t g m v e 18 -> R g 1 -> A m e k j w w o b j o y w w b u h a y p t 20 -> T Dupa ce am numarat literele fiecarui cuvant am pus in loc de numarul de litere, litera din alfabet care se afla la pozitia data de numarul literelor. Asa ca am obtinut: FELICITARI ESTI UN ROMAN ADEVARAT. Alte challenge-uri: [Easy] The big fat panda si The Eye of ... Multumesc @Usr6

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NEW YORK CITY – A New York man has been arrested after he reportedly made over a million dollars selling Chuck E. Cheese tokens as Bitcoins on the streets. Marlon Jensen, 36, was arrested a Sunday morning when NYPD stormed his home. NYPD received calls from the fraud victims that someone had sold them “Bitcoins”, only to find out there actually was no tangible bitcoin currency available. NYPD found $1.1 Million of cash inside Marlons home. According to police, Marlon had scratched off most of the Chuck E. Cheese engravements on the coins, and would write “B” on each coin with permanent marker. As many should know already, Bitcoin is a crypto currency and payment system that has recently received unprecedented popularity and value, with each bitcoin currently worth $18,950 USD. Although Bitcoin isn’t actually a tangible form of currency, that hasn’t stopped some people from successfully selling “bitcoins” to people using irrelevant gold coins, in this case Chuck E. Cheese Tokens. “People are retarded haha”, said NYPD Officer Michael West, “My 8 year old son would know those weren’t bitcoins and lord knows he’s not the brightest”. Marlon is currently being charged with fraud and can face up to 5 years in federal prison. Sursa: https://www.huzlers.com/bitcoin-scam-man-arrested-after-making-over-1-million-selling-chuck-e-cheese-tokens-as-bitcoins/

Aka dai teapa

@Zatarra, ce preferi: iMac sau garsoniera?

Pentru inceput il platesc eu.